Hello Kuniyuki,
On Wed, Jun 07, 2023 at 10:31:42AM -0700, Kuniyuki Iwashima wrote:
> > +/* This is the most common ioctl prep function, where the result (4 bytes) is
> > + * copied back to userspace if the ioctl() returns successfully. No input is
> > + * copied from userspace as input argument.
> > + */
> > +static int sock_ioctl_out(struct sock *sk, unsigned int cmd, void __user *arg)
> > +{
> > + int ret, karg = 0;
> > +
> > + ret = sk->sk_prot->ioctl(sk, cmd, &karg);
>
> We need READ_ONCE(sk->sk_prot) as IPv4 conversion or ULP chnage could
> occur at the same time.
Thanks for the heads-up. I would like to pick you brain and understand
a bit more about READ_ONCE() and what is the situation that READ_ONCE()
will solve.
Is the situation related to when sock_ioctl_out() start to execute, and
"sk->sk_prot" changes in a different thread? If that is the case, the
arguments (cmd and arg) will be from the "previous" instance.
Also, grepping for "sk->sk_prot->", I see more than a bunch of calls
that do not use READ_ONCE() barrier. Why is this case different?
Thank you
