Use list_is_singular() instead of open-coding.
Signed-off-by: Geliang Tang <geliangtang@xxxxxxxxx>
---
include/net/sctp/sctp.h | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)
diff --git a/include/net/sctp/sctp.h b/include/net/sctp/sctp.h
index f8bcb75bb044..e3bd198b00ae 100644
--- a/include/net/sctp/sctp.h
+++ b/include/net/sctp/sctp.h
@@ -412,7 +412,7 @@ static inline void sctp_skb_set_owner_r(struct sk_buff *skb, struct sock *sk)
/* Tests if the list has one and only one entry. */
static inline int sctp_list_single_entry(struct list_head *head)
{
- return (head->next != head) && (head->next == head->prev);
+ return list_is_singular(head);
}
static inline bool sctp_chunk_pending(const struct sctp_chunk *chunk)
--
2.17.1
