Re: How to restrict SCTP abort during a process crash

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On Tue, Dec 12, 2017 at 10:21:31PM +0530, Ashok Kumar wrote:
> Hi,
> 
> 
> 
> We are using LKSCTP in our LTE product (HeNBGW). We have
> high-availability support also in our product. In case of any failure
> on active VM, standby VM will take over active role and all the SCTP
> associations will be moved to that new active VM. The associations
> should be moved transparent to the peers (a kind of SCTP reset before
> SCTP heartbeat expires on the peer nodes).
> 
> 
> 
> But the problem that we face is that when a process crashes on active
> VM, the LKSCTP stack immediately sends SCTP abort to the peers for all
> associations before the system goes down completely. This creates
> confusion with the peers. Is there any way to avoid sending SCTP abort
> message in this scenario? If yes, please let us know how to do the
> same? If it needs LKSCTP kernel code change, please give pointers on
> what and where to change.
> 
> 
> 
> P.S: We tried to block the abort messages by dynamically using
> IPtables through signal handler (for signal 11 and 6). But this did
> not work.
> 
> 
> 
> A quick response will be highly appreciated.
> 
You're not going to be able to reliably block ABORTS, or any packet only on a
crash condition, just because the stack has points that operates asynchronously
to the process.  

About the closest thing that I could think of would be to write a custom
iptables rule to match on ABORT packets and send them to the NFQUEUE target.
Write a userspace handler process for queue targeted packets which in turn just
holds the abort packet for at least one cluster live heartbeat time (I'm
assuming here that, being a clustered system it has some sort of liveness
check).  Doing this hold may allow the cluster to shift to the new vm in a
failure situation before your queue handler process releases any abort packets
that it has, while in the event there is no failover, it will just release the
abort a little late.

I can't really recommend that approach mind you (its a horrid hack, and will
likely cause other protocol issues), but its all I can think of at the moment.

Regards
Neil

> 
> 
> Thanks,
> 
> Ashok
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