On 04/03/2013 09:51 AM, Neil Horman wrote:
On Wed, Apr 03, 2013 at 09:02:28PM +0800, Wei Yongjun wrote:From: Wei Yongjun <yongjun_wei@xxxxxxxxxxxxxxxxx> Fix to return a negative error code from the error handling case instead of 0, as returned elsewhere in this function. Signed-off-by: Wei Yongjun <yongjun_wei@xxxxxxxxxxxxxxxxx> --- net/sctp/socket.c | 5 +++-- 1 file changed, 3 insertions(+), 2 deletions(-) diff --git a/net/sctp/socket.c b/net/sctp/socket.c index dd21ae3..f631c5f 100644 --- a/net/sctp/socket.c +++ b/net/sctp/socket.c @@ -1119,9 +1119,10 @@ static int __sctp_connect(struct sock* sk, /* Make sure the destination port is correctly set * in all addresses. */ - if (asoc && asoc->peer.port && asoc->peer.port != port) + if (asoc && asoc->peer.port && asoc->peer.port != port) { + err = -EINVAL; goto out_free; - + } /* Check if there already is a matching association on the * endpoint (other than the one created here). -- To unsubscribe from this list: send the line "unsubscribe linux-sctp" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.htmlActually, I think you can remove that entire if statement (as well as some checks further down). Looking at the net-next trees __sctp_connect, it appears that asoc is set to NULL at the top of the function, and not assigned to anything else until the call to sctp_association_new much farther down (line 1201). That means the above if statement, as well as this: if (asoc2 && asoc2 != asoc) { and this: if (!asoc) { will always be false, false, and true, respectively.
No, I don't think you can. Consider a case of sctp_connectx() where each address specified in connectx has a different destination port.
First time through the loop, we'll create the association and set the peer.port. The second time through the loop, we'll compare the that port to the port specified in the second address. If the ports do not match, we need to stop.
-vlad
Regards Neil
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