On Wed, 2008-05-21 at 23:45 -0700, Paul E. McKenney wrote:
> Some RCU-related questions interspersed below, for example, how are
> updates protected?
Only one CNIC driver will ever register with the BNX2 driver. The main
purpose of using RCU is so that the fast path can avoid locking when
handling interrupt events from the hardware.
> > +
> > +static void bnx2_setup_cnic_irq_info(struct bnx2 *bp)
> > +{
> > + struct cnic_ops *c_ops;
> > + struct cnic_eth_dev *cp = &bp->cnic_eth_dev;
> > + struct bnx2_napi *bnapi = &bp->bnx2_napi[0];
> > + int sb_id;
> > +
> > + rcu_read_lock();
> > + c_ops = rcu_dereference(bp->cnic_ops);
> > + if (!c_ops)
> > + goto done;
>
> Given that c_ops is unused below, what is happening here? What prevents
> bp->cnic_ops from becoming NULL immediately after we test it? And if
> it is OK for bp->cnic_ops to become NULL immediately after we test it,
> why are we bothering to test it?
You are right. We should just unconditionally set up the IRQ
information without checking for c_ops. The data structures we set up
below are owned by us.
>
> > +
> > + if (bp->flags & BNX2_FLAG_USING_MSIX) {
> > + cp->drv_state |= CNIC_DRV_STATE_USING_MSIX;
> > + bnapi->cnic_present = 0;
> > + sb_id = BNX2_CNIC_VEC;
> > + cp->irq_arr[0].irq_flags |= CNIC_IRQ_FL_MSIX;
> > + } else {
> > + cp->drv_state &= ~CNIC_DRV_STATE_USING_MSIX;
> > + bnapi->cnic_tag = bnapi->last_status_idx;
> > + bnapi->cnic_present = 1;
> > + sb_id = 0;
> > + cp->irq_arr[0].irq_flags &= !CNIC_IRQ_FL_MSIX;
> > + }
> > +
> > + cp->irq_arr[0].vector = bp->irq_tbl[sb_id].vector;
> > + cp->irq_arr[0].status_blk = (void *) ((unsigned long) bp->status_blk +
> > + (BNX2_SBLK_MSIX_ALIGN_SIZE * sb_id));
> > + cp->irq_arr[0].status_blk_num = sb_id;
> > + cp->num_irq = 1;
> > +
> > +done:
> > + rcu_read_unlock();
> > +}
> > +
> > +static int bnx2_register_cnic(struct net_device *dev, struct cnic_ops *ops,
> > + void *data)
> > +{
> > + struct bnx2 *bp = netdev_priv(dev);
> > + struct cnic_eth_dev *cp = &bp->cnic_eth_dev;
> > +
> > + if (ops == NULL)
> > + return -EINVAL;
> > +
> > + if (!try_module_get(ops->cnic_owner))
> > + return -EBUSY;
> > +
> > + bp->cnic_data = data;
> > + rcu_assign_pointer(bp->cnic_ops, ops);
>
> What prevents multiple tasks from doing this assignment concurrently?
As I said above, only one CNIC driver will ever register.
>
> > +
> > + cp->num_irq = 0;
> > + cp->drv_state = CNIC_DRV_STATE_REGD;
> > +
> > + bnx2_setup_cnic_irq_info(bp);
> > +
> > + return 0;
> > +}
> > +
> > +static int bnx2_unregister_cnic(struct net_device *dev)
> > +{
> > + struct bnx2 *bp = netdev_priv(dev);
> > + struct bnx2_napi *bnapi = &bp->bnx2_napi[0];
> > + struct cnic_eth_dev *cp = &bp->cnic_eth_dev;
> > +
> > + cp->drv_state = 0;
> > + module_put(bp->cnic_ops->cnic_owner);
> > + bnapi->cnic_present = 0;
> > + rcu_assign_pointer(bp->cnic_ops, NULL);
>
> What prevents this from running concurrently with bnx2_register_cnic()?
We expect the CNIC driver to be well behaved and will only unregister
after successfully registered.
>
> > + synchronize_rcu();
>
> The caller is responsible for freeing up the old bp->cnic_ops structure?
> Or is this structure statically allocated?
>
> If so, is the idea to delay return until all prior calls through the
> old ops structure have completed?
The cnic_ops contain call back function pointers to the CNIC driver. We
want to make sure that those calls have completed (in the fast path)
before continuing.
>
> > + return 0;
> > +}
> > +
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