Re: [PATCH] fix leftover from default sdev attribute switch

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On Wed, 2007-09-26 at 20:32 +0200, Kay Sievers wrote:
> On Wed, 2007-09-26 at 13:23 -0500, James Bottomley wrote:
> > On Wed, 2007-09-26 at 19:54 +0200, Kay Sievers wrote:
> > > Hi James,
> > > seems we miss the following fix in the current tree.
> > > 
> > > From: Kay Sievers <kay.sievers@xxxxxxxx>
> > > Subject: [SCSI] fix scsi_is_sdev_device() after switch to default sdev attributes
> > > 
> > > Signed-off-by: Kay Sievers <kay.sievers@xxxxxxxx>
> > > ---
> > > diff --git a/drivers/scsi/scsi_sysfs.c b/drivers/scsi/scsi_sysfs.c
> > > index 0088c4d..8e880ef 100644
> > > --- a/drivers/scsi/scsi_sysfs.c
> > > +++ b/drivers/scsi/scsi_sysfs.c
> > > @@ -995,7 +995,7 @@ void scsi_sysfs_device_initialize(struct scsi_device *sdev)
> > >  
> > >  int scsi_is_sdev_device(const struct device *dev)
> > >  {
> > > -	return dev->release == scsi_device_dev_release;
> > > +	return dev->type == &scsi_dev_type;
> > 
> > This will make the check different from all the others in the
> > mid-layer ... is there any reason to change it?
> 
> The release function moved to device_type, so the "hack" with checking
> for the release pointer at the device doesn't work anymore. With Hannes'
> patches here on the list, the target and host will get device_type too,
> and the same way of matching.

So all the other ones are incorrect and need fixing? That's

hosts.c:int scsi_is_host_device(const struct device *dev)
scsi_scan.c:int scsi_is_target_device(const struct device *dev)
scsi_transport_fc.c:int scsi_is_fc_rport(const struct device *dev)
scsi_transport_fc.c:int scsi_is_fc_vport(const struct device *dev)
scsi_transport_iscsi.c:static int iscsi_is_session_dev(const struct
device *dev)
scsi_transport_iscsi.c:static int iscsi_is_conn_dev(const struct device
*dev)
scsi_transport_sas.c:int scsi_is_sas_phy(const struct device *dev)
scsi_transport_sas.c:int scsi_is_sas_port(const struct device *dev)
scsi_transport_sas.c:int scsi_is_sas_rphy(const struct device *dev)


Checking the release function is the way each of these passes the test.

James


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