Re: [PATCH 05/12] pm80xx : Increase timeout for pm80xx mpi_uninit_check.

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On Thu, Oct 31, 2019 at 6:12 AM Deepak Ukey <deepak.ukey@xxxxxxxxxxxxx> wrote:
>
> From: ianyar <ianyar@xxxxxxxxxx>
>
> The function  mpi_uninit_check takes longer for inbound doorbell
> register to be cleared. Increased the timeout substantially so
> that the driver does not fail to load.
>
> Signed-off-by: ianyar <ianyar@xxxxxxxxxx>
> Signed-off-by: Deepak Ukey <deepak.ukey@xxxxxxxxxxxxx>
> Signed-off-by: Viswas G <Viswas.G@xxxxxxxxxxxxx>
Looks fine.
Acked-by: Jack Wang <jinpu.wang@xxxxxxxxxxxxxxx>
> ---
>  drivers/scsi/pm8001/pm80xx_hwi.c | 4 ++--
>  drivers/scsi/pm8001/pm80xx_hwi.h | 3 +++
>  2 files changed, 5 insertions(+), 2 deletions(-)
>
> diff --git a/drivers/scsi/pm8001/pm80xx_hwi.c b/drivers/scsi/pm8001/pm80xx_hwi.c
> index 6057610263c1..9d04e5cfffb4 100644
> --- a/drivers/scsi/pm8001/pm80xx_hwi.c
> +++ b/drivers/scsi/pm8001/pm80xx_hwi.c
> @@ -735,9 +735,9 @@ static int mpi_init_check(struct pm8001_hba_info *pm8001_ha)
>         pm8001_cw32(pm8001_ha, 0, MSGU_IBDB_SET, SPCv_MSGU_CFG_TABLE_UPDATE);
>         /* wait until Inbound DoorBell Clear Register toggled */
>         if (IS_SPCV_12G(pm8001_ha->pdev)) {
> -               max_wait_count = 4 * 1000 * 1000;/* 4 sec */
> +               max_wait_count = SPCV_DOORBELL_CLEAR_TIMEOUT;
>         } else {
> -               max_wait_count = 2 * 1000 * 1000;/* 2 sec */
> +               max_wait_count = SPC_DOORBELL_CLEAR_TIMEOUT;
>         }
>         do {
>                 udelay(1);
> diff --git a/drivers/scsi/pm8001/pm80xx_hwi.h b/drivers/scsi/pm8001/pm80xx_hwi.h
> index dc9ab7689060..701951a0f715 100644
> --- a/drivers/scsi/pm8001/pm80xx_hwi.h
> +++ b/drivers/scsi/pm8001/pm80xx_hwi.h
> @@ -220,6 +220,9 @@
>  #define SAS_DOPNRJT_RTRY_TMO            128
>  #define SAS_COPNRJT_RTRY_TMO            128
>
> +#define SPCV_DOORBELL_CLEAR_TIMEOUT    (30 * 1000 * 1000) /* 30 sec */
> +#define SPC_DOORBELL_CLEAR_TIMEOUT     (15 * 1000 * 1000) /* 15 sec */
> +
>  /*
>    Making ORR bigger than IT NEXUS LOSS which is 2000000us = 2 second.
>    Assuming a bigger value 3 second, 3000000/128 = 23437.5 where 128
> --
> 2.16.3
>



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