One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example: struct foo { int stuff; void *entry[]; }; instance = kzalloc(sizeof(struct foo) + sizeof(void *) * count, GFP_KERNEL); Instead of leaving these open-coded and prone to type mistakes, we can now use the new struct_size() helper: instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL); This code was detected with the help of Coccinelle. Signed-off-by: Gustavo A. R. Silva <gustavo@xxxxxxxxxxxxxx> --- drivers/scsi/mvsas/mv_init.c | 6 +++--- 1 file changed, 3 insertions(+), 3 deletions(-) diff --git a/drivers/scsi/mvsas/mv_init.c b/drivers/scsi/mvsas/mv_init.c index 030d911ee374..cd6ba7ed0ab4 100644 --- a/drivers/scsi/mvsas/mv_init.c +++ b/drivers/scsi/mvsas/mv_init.c @@ -366,9 +366,9 @@ static struct mvs_info *mvs_pci_alloc(struct pci_dev *pdev, struct mvs_info *mvi = NULL; struct sas_ha_struct *sha = SHOST_TO_SAS_HA(shost); - mvi = kzalloc(sizeof(*mvi) + - (1L << mvs_chips[ent->driver_data].slot_width) * - sizeof(struct mvs_slot_info), GFP_KERNEL); + mvi = kzalloc(struct_size(mvi, slot_info, + (1L << mvs_chips[ent->driver_data].slot_width)), + GFP_KERNEL); if (!mvi) return NULL; -- 2.20.1