On 07.09.21 12:24, Pierre Morel wrote:
On 9/6/21 8:37 PM, David Hildenbrand wrote:
On 03.08.21 10:26, Pierre Morel wrote:
We let the userland hypervisor know if the machine support the CPU
topology facility using a new KVM capability: KVM_CAP_S390_CPU_TOPOLOGY.
The PTF instruction will report a topology change if there is any change
with a previous STSI_15_2 SYSIB.
Changes inside a STSI_15_2 SYSIB occur if CPU bits are set or clear
inside the CPU Topology List Entry CPU mask field, which happens with
changes in CPU polarization, dedication, CPU types and adding or
removing CPUs in a socket.
The reporting to the guest is done using the Multiprocessor
Topology-Change-Report (MTCR) bit of the utility entry of the guest's
SCA which will be cleared during the interpretation of PTF.
To check if the topology has been modified we use a new field of the
arch vCPU to save the previous real CPU ID at the end of a schedule
and verify on next schedule that the CPU used is in the same socket.
We deliberatly ignore:
- polarization: only horizontal polarization is currently used in linux.
- CPU Type: only IFL Type are supported in Linux
- Dedication: we consider that only a complete dedicated CPU stack can
take benefit of the CPU Topology.
Signed-off-by: Pierre Morel <pmorel@xxxxxxxxxxxxx>
@@ -228,7 +232,7 @@ struct kvm_s390_sie_block {
__u8 icptcode; /* 0x0050 */
__u8 icptstatus; /* 0x0051 */
__u16 ihcpu; /* 0x0052 */
- __u8 reserved54; /* 0x0054 */
+ __u8 mtcr; /* 0x0054 */
#define IICTL_CODE_NONE 0x00
#define IICTL_CODE_MCHK 0x01
#define IICTL_CODE_EXT 0x02
@@ -246,6 +250,7 @@ struct kvm_s390_sie_block {
#define ECB_TE 0x10
#define ECB_SRSI 0x04
#define ECB_HOSTPROTINT 0x02
+#define ECB_PTF 0x01
From below I understand, that ECB_PTF can be used with stfl(11) in the hypervisor.
What is to happen if the hypervisor doesn't support stfl(11) and we consequently cannot use ECB_PTF? Will QEMU be able to emulate PTF fully?
Yes.
Do we want that? I do not think so. Other OSes (like zOS) do use PTF in there low level interrupt handler, so PTF must be really fast.
I think I would prefer that in that case the guest will simply not see stfle(11).
So the user can still specify the topology but the guest will have no interface to query it.