[PATCH v3] rtc: bd70528: enable the device's wakeup in the last step of .probe()

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Current code leaves the device's wakeup enabled in the error path of
.probe(), which results in a memory leak. Call device_init_wakeup() as
the last step in the .probe() to avoid this leak.

This bug was found by an experimental static analysis tool that I am
developing.

Fixes: 32a4a4ebf768 ("rtc: bd70528: Initial support for ROHM bd70528 RTC")
Signed-off-by: Joe Hattori <joe@xxxxxxxxxxxxxxxxxxxxx>
---
Changes in V2:
- Move the device_init_wakeup() to the last step of the .probe() to make
  the cleanup simpler.
---
 drivers/rtc/rtc-bd70528.c | 10 ++++++----
 1 file changed, 6 insertions(+), 4 deletions(-)

diff --git a/drivers/rtc/rtc-bd70528.c b/drivers/rtc/rtc-bd70528.c
index 954ac4ef53e8..d5cc4993f918 100644
--- a/drivers/rtc/rtc-bd70528.c
+++ b/drivers/rtc/rtc-bd70528.c
@@ -312,9 +312,6 @@ static int bd70528_probe(struct platform_device *pdev)
 		}
 	}
 
-	device_set_wakeup_capable(&pdev->dev, true);
-	device_wakeup_enable(&pdev->dev);
-
 	rtc = devm_rtc_allocate_device(&pdev->dev);
 	if (IS_ERR(rtc)) {
 		dev_err(&pdev->dev, "RTC device creation failed\n");
@@ -331,7 +328,12 @@ static int bd70528_probe(struct platform_device *pdev)
 	if (ret)
 		return ret;
 
-	return devm_rtc_register_device(rtc);
+	ret = devm_rtc_register_device(rtc);
+	if (ret)
+		return ret;
+
+	device_init_wakeup(&pdev->dev, true);
+	return 0;
 }
 
 static const struct platform_device_id bd718x7_rtc_id[] = {
-- 
2.34.1





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