On Sat, 26 Mar 2022 11:07:03 +0000
John Keeping <john@xxxxxxxxxxxx> wrote:
> > > > + print_time(cpu_tasks[i]->runtime, '_');
> > > > + printf(" (%%%lld)\n", (task->runtime * 100) / total_time);
> > >
> > > Is there a reason for using the CPU-specific runtime for the value and
> > > the total runtime for the percentage?
> > >
> > > I expected the percentage to be the percentage of this CPU's time spend
> > > running the task.
> >
> > We modify it so that each CPU has the same run time, unless there's missed
> > events at the start (later patches), and then we change total_time to be
> > the total time of the events on the CPU and not the entire trace.
>
> I think we're talking about different things here, I probably wasn't
> entirely clear about this. It's the numerator of this division that I'm
> concerned about and I wonder if this should be:
>
> (cpu_tasks[i]->runtime * 100) / total_time
Ah, I did misunderstand you. Yes, that's a typo. Thanks for pointing
that out. I'll go fix it.
-- Steve
