On Tue, 26 Oct 2021 10:38:27 +0200
Daniel Bristot de Oliveira <bristot@xxxxxxxxxx> wrote:
> >> * osnoise_register_instance - register a new trace instance
> >> *
> >> @@ -2048,6 +2066,16 @@ static int osnoise_workload_start(void)
> >> {
> >> int retval;
> >>
> >> + /*
> >> + * Instances need to be registered after calling workload
> >> + * start. Hence, if there is already an instance, the
> >> + * workload was already registered. Otherwise, this
> >> + * code is on the way to register the first instance,
> >> + * and the workload will start.
> >> + */
> >> + if (osnoise_has_registered_instances())
> >> + return 0;
> >
> > Looking at how this is checked before being called, it really should
> > return -1, as it is an error if this is called with instances active.
>
> Hum.... maybe my explanation is not good enough. It is not a problem if it is
> called with active instances. It would be an error if the same instance was
> already registered at this point, but that was checked before. Here it is
> checking for other instances that should have enabled the workload.
>
> Does updating the comment with the one below helps?
No need.
> >> @@ -2096,7 +2131,11 @@ static void osnoise_tracer_start(struct trace_array *tr)
> >> {
> >> int retval;
> >>
> >> - if (osnoise_has_registered_instances())
> >> + /*
> >> + * If the instance is already registered, there is no need to
> >> + * register it again.
> >> + */
> >> + if (osnoise_instance_registered(tr))
My eyes missed that you removed the osnoise_has_registered_instances() for
the osnoise_instance_registered(tr), and thought you were doing the same
test twice.
My mistake. I need to not review patches at the end of the day when I'm
ready to go to sleep.
-- Steve
