The to-be-fixed commit rightfully prevented that the registers will be
cleared. However, the index must be cleared. Otherwise a read message
will re-issue the last work. Fix it and add a comment describing the
situation.
Fixes: c422b6a63024 ("i2c: testunit: don't erase registers after STOP")
Signed-off-by: Wolfram Sang <wsa+renesas@xxxxxxxxxxxxxxxxxxxx>
---
drivers/i2c/i2c-slave-testunit.c | 7 +++++++
1 file changed, 7 insertions(+)
diff --git a/drivers/i2c/i2c-slave-testunit.c b/drivers/i2c/i2c-slave-testunit.c
index ca43e98cae1b..23a11e4e9256 100644
--- a/drivers/i2c/i2c-slave-testunit.c
+++ b/drivers/i2c/i2c-slave-testunit.c
@@ -118,6 +118,13 @@ static int i2c_slave_testunit_slave_cb(struct i2c_client *client,
queue_delayed_work(system_long_wq, &tu->worker,
msecs_to_jiffies(10 * tu->regs[TU_REG_DELAY]));
}
+
+ /*
+ * Reset reg_idx to avoid that work gets queued again in case of
+ * STOP after a following read message. But do not clear TU regs
+ * here because we still need them in the workqueue!
+ */
+ tu->reg_idx = 0;
break;
case I2C_SLAVE_WRITE_REQUESTED:
--
2.43.0
