Re: [PATCH V3] ARM: shmobile: Rework the PMIC IRQ line quirk

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On 06/11/2018 03:03 PM, Geert Uytterhoeven wrote:
> Hi Marek,

Hi,

> On Mon, Jun 11, 2018 at 2:15 PM Marek Vasut <marek.vasut@xxxxxxxxx> wrote:
>> On 06/11/2018 11:56 AM, Geert Uytterhoeven wrote:
>>> On Mon, Jun 4, 2018 at 7:59 PM Marek Vasut <marek.vasut@xxxxxxxxx> wrote:
>>>> Rather than hard-coding the quirk topology, which stopped scaling,
>>>> parse the information from DT. The code looks for all compatible
>>>> PMICs -- da9036 and da9210 -- and checks if their IRQ line is tied
>>>
>>> da9063
>>>
>>>> to the same pin. If so, the code sends a matching sequence to the
>>>> PMIC to deassert the IRQ.
> 
>>>> @@ -122,7 +143,13 @@ static struct notifier_block regulator_quirk_nb = {
>>>>
>>>>  static int __init rcar_gen2_regulator_quirk(void)
>>>>  {
>>>> -       u32 mon;
>>>> +       struct device_node *np;
>>>> +       const struct of_device_id *id;
>>>> +       struct regulator_quirk *quirk;
>>>> +       struct regulator_quirk *pos;
>>>> +       struct of_phandle_args *argsa, *argsb;
>>>> +       u32 mon, addr;
>>>> +       int ret;
>>>
>>> Some people prefer "Reverse Christmas Tree Ordering", i.e. longest line first.
>>>
>>>>
>>>>         if (!of_machine_is_compatible("renesas,koelsch") &&
>>>>             !of_machine_is_compatible("renesas,lager") &&
>>>> @@ -130,6 +157,45 @@ static int __init rcar_gen2_regulator_quirk(void)
>>>>             !of_machine_is_compatible("renesas,gose"))
>>>>                 return -ENODEV;
>>>
>>> I think the board checks above can be removed. That will auto-enable the
>>> fix on e.g. Porter (once its regulators have ended up in DTS, of course).
>>
>> Removing the check would also enable it on boards where we don't want
>> this enabled, so I'd prefer to keep the check to avoid strange surprises.
> 
> Like, Porter? ;-)

I'm adding Porter in a separate patch.

>>>> +               ret = of_property_read_u32(np, "reg", &addr);
>>>> +               if (ret)
>>>> +                       return ret;
>>>
>>> I think it's safer to skip this entry and continue, after calling
>>> kfree(quirk), of course.
>>>
>>>> +
>>>> +               quirk->id = id;
>>>> +               quirk->i2c_msg.addr = addr;
>>>> +               quirk->shared = false;
>>>> +
>>>> +               ret = of_irq_parse_one(np, 0, &quirk->irq_args);
>>>> +               if (ret)
>>>> +                       return ret;
>>>
>>> kfree(quirk) and continue...
>>
>> I wonder if it shouldn't rather free the entire list and abort ?
> 
> "Be strict when sending, be liberal when receiving."

Meaning ? I think "the language barrier is protecting me" (TM)

-- 
Best regards,
Marek Vasut



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