Re: [PATCH 2/2] [RFC] base: soc: Allow early registration of a single SoC device

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On Thu, Mar 9, 2017 at 7:18 PM, Geert Uytterhoeven
<geert+renesas@xxxxxxxxx> wrote:
> commit 1da1b3628df34a2a ("base: soc: Early register bus when needed")
> added support for early registration of SoC devices from a
> core_initcall().  However, some drivers need to check the SoC revision
> from an early_initcall(), which is even earlier.
>
> While registering the SoC bus and device, and using soc_device_match(),
> from an early_initcall() do work, the "soc" directory and the "soc0"
> file end up wrongly in the sysfs root, as the "bus" resp. "devices"
> directories haven't been created yet.
>
> To fix this, allow to register a single SoC device early on.
> As long as the SoC bus isn't registered, soc_device_match() just
> matches against this early device.
> When the SoC bus is registered later, the early device is registered for
> real.
>
> Note that soc_device_register() returns NULL (no error, but also not a
> valid pointer) when registering an early device.  Hence platform devices
> cannot be instantiated as children of the "soc0" node representing an
> early SoC device.  This should not be an issue, as that practice has
> been deprecated for new platforms.
>
> Signed-off-by: Geert Uytterhoeven <geert+renesas@xxxxxxxxx>
> ---
> Is there a better way to fix this?
> While I believe all current users register a single SoC device, we may
> want to register multiple SoC devices in the future?
>
> soc_device_match() itself is completely independent from sysfs, but the
> sysfs operations are tied intimately to the driver core.
>
> The "bus" and "devices" directories are created from do_basic_setup() ->
> driver_init() -> devices_init() / buses_init(), which runs in between
> do_pre_smp_initcalls() (early_initcall()) and do_initcalls().

I'd prefer to not have to do the early registration at all and have fewer
special cases. Can you list a specific example that requires this?

If we want to do early registration, then your implementation seems
fine to me.

     Arnd



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