On Tue, Apr 24, 2018 at 06:05:58PM -0500, Bjorn Helgaas wrote: > > + /* > > + * There is only one bridge on the bus so it gets all available > > + * resources which it can then distribute to the possible > > + * hotplug bridges below. > > + */ > > + if ((hotplug_bridges == 0 && normal_bridges == 1) || > > + (hotplug_bridges == 1 && normal_bridges == 0)) { > > if (hotplug_bridges + normal_bridges == 1) { > > Don't repost just for this; I can fold it in if you agree. I agree, looks better like that. Thanks!