On Tue, 2024-10-22 at 16:08 +0200, Takashi Iwai wrote: > On Tue, 15 Oct 2024 20:51:12 +0200, > Philipp Stanner wrote: > > > > pci_intx() is a hybrid function which can sometimes be managed > > through > > devres. To remove this hybrid nature from pci_intx(), it is > > necessary to > > port users to either an always-managed or a never-managed version. > > > > hda_intel enables its PCI-Device with pcim_enable_device(). Thus, > > it needs > > the always-managed version. > > > > Replace pci_intx() with pcim_intx(). > > > > Signed-off-by: Philipp Stanner <pstanner@xxxxxxxxxx> > > --- > > sound/pci/hda/hda_intel.c | 2 +- > > 1 file changed, 1 insertion(+), 1 deletion(-) > > > > diff --git a/sound/pci/hda/hda_intel.c b/sound/pci/hda/hda_intel.c > > index b4540c5cd2a6..b44ca7b6e54f 100644 > > --- a/sound/pci/hda/hda_intel.c > > +++ b/sound/pci/hda/hda_intel.c > > @@ -786,7 +786,7 @@ static int azx_acquire_irq(struct azx *chip, > > int do_disconnect) > > } > > bus->irq = chip->pci->irq; > > chip->card->sync_irq = bus->irq; > > - pci_intx(chip->pci, !chip->msi); > > + pcim_intx(chip->pci, !chip->msi); > > return 0; > > } > > > > Hm, it's OK-ish to do this as it's practically same as what > pci_intx() > currently does. But, the current code can be a bit inconsistent > about > the original intx value. pcim_intx() always stores !enable to > res->orig_intx unconditionally, and it means that the orig_intx value > gets overridden at each time pcim_intx() gets called. Yes. > > Meanwhile, HD-audio driver does release and re-acquire the interrupt > after disabling MSI when something goes wrong, and pci_intx() call > above is a part of that procedure. So, it can rewrite the > res->orig_intx to another value by retry without MSI. And after the > driver removal, it'll lead to another state. I'm not sure that I understand this paragraph completely. Still, could a solution for the driver on the long-term just be to use pci_intx()? > > In anyway, as it doesn't change the current behavior, feel free to > take my ack for now: > > Acked-by: Takashi Iwai <tiwai@xxxxxxx> Thank you, P. > > > thanks, > > Takashi >