Re: [PATCH 1/3] arm: Rename PMD_ORDER to PMD_TABLE_ORDER

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On Thu, Jul 15, 2021 at 07:37:27PM +0100, Russell King (Oracle) wrote:
> On Thu, Jul 15, 2021 at 07:10:54PM +0100, Matthew Wilcox wrote:
> > On Thu, Jul 15, 2021 at 05:47:41PM +0100, Russell King (Oracle) wrote:
> > > On Thu, Jul 15, 2021 at 02:46:10PM +0100, Matthew Wilcox (Oracle) wrote:
> > > > This is the order of the page table allocation, not the order of a PMD.
> > > > -#define PMD_ORDER	3
> > > > +#define PMD_TABLE_ORDER	3
> > > >  #else
> > > >  #define PG_DIR_SIZE	0x4000
> > > > -#define PMD_ORDER	2
> > > > +#define PMD_TABLE_ORDER	2
> > > 
> > > I think PMD_ENTRY_ORDER would make more sense here - this is the
> > > power-of-2 of an individual PMD entry, not of the entire table.
> > 
> > But ... we have two kinds of PMD entries.  We have the direct entry that
> > points to a 1-16MB sized chunk of memory, and we have the table entry that
> > points to a 4k-32k chunk of memory that contains PTEs.  So I don't think
> > calling it 'entry' order actually disambiguates anything.  That's why
> > I went with 'table' -- I can't think of anything else to call it!
> > PMD_PTE_ARRAY_ORDER doesn't seem like an improvement to me ...
> 
> There may be two kinds of PMD entries, but that isn't relevant here.
> Going back to the original terminology, 1 << PMD_ORDER here is the
> size of each PMD entry. It doesn't have anything to do with how much
> memory is being mapped by each entry.

Oh.  Oh!  So, 'order' is usually a shift that is _added on to_ the
PAGE_SHIFT in order to find how many bytes are in question.  See
include/asm-generic/getorder.h.

Now, PMD_SHIFT is already in use, but perhaps what is meant here is
PMD_ENTRY_SHIFT?

> I think what is confusing you is stuff like:
> 
>         add     r0, r4, #KERNEL_OFFSET >> (SECTION_SHIFT - PMD_ORDER)
> 
> r4 is the base address of the page tables, and r0 is the address of
> the entry we want to manipulate for "KERNEL_OFFSET" - which is the
> virtual address. 1 << SECTION_SHIFT is how much memory each entry
> maps (and this is fixed here - there's no variability as you suggest
> above.)

(the variability I intended above was more to accommodate architectural
differences; I hate to use x86-specific numbers like 4KiB and 2MiB)

> Effectively, the calculation above is:
> 
> 	index = KERNEL_OFFSET >> SECTION_SHIFT;
> 	pmd_entry_size = 1 << PMD_ORDER;
> 	r0 = base + index * pmd_entry_size;
> 
> but in a single instruction as we can be sure that KERNEL_OFFSET will
> have zeros as the low bits after shifting by SECTION_SHIFT - PMD_ORDER.
> 
> Hope this helps to explain what this PMD_ORDER is actually doing here.

Thank you, yes, I was terminally confused.



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