Hello, I'm trying to understand what's the exact behavior of the interleaved allocation in libnuma. I have two questions, the first regarding numa_alloc_interleaved() and the second regarding numactl. Suppose I'm running in a 4-node machine. 1. What happens when I try to allocate 100 pages with a call like this: numa_alloc_interleaved(100 * numa_pagesize()) I can think of two possible allocation schemes: a. Pages 0-24 are allocated to node 0, pages 25-49 are allocated to node 1, pages 50-74 are allocated on node 2 and pages 75-99 are allocated on node 3. b. Pages 0,4,8... are allocated on node 0, pages 1,5,9... are allocated on node 1 and so on 2. What's the effect of using numactl --interleaved=0,1,2,3 -- ./myprog? I would assume it "substitutes" any malloc's to numa_alloc_interleaved(), but I'm not sure if it's just that. Thank you, Martin
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