[PATCH] sched: report correct state for TASK_IDLE | TASK_FREEZABLE

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task_state_index() ignores uninteresting state flags (such as
TASK_FREEZABLE) for most states, but for TASK_IDLE and TASK_RTLOCK_WAIT
it does not.
So if a task is waiting TASK_IDLE|TASK_FREEZABLE it gets incorrectly
reported as TASK_UNINTERRUPTIBLE or "D".  (it is planned for nfsd to
change to use this state).

Fix this by only testing the interesting bits and not the irrelevant
bits in __task_state_index()

Signed-off-by: NeilBrown <neilb@xxxxxxx>
---
 include/linux/sched.h | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/include/linux/sched.h b/include/linux/sched.h
index 177b3f3676ef..c0a21a3b106c 100644
--- a/include/linux/sched.h
+++ b/include/linux/sched.h
@@ -1671,7 +1671,7 @@ static inline unsigned int __task_state_index(unsigned int tsk_state,
 
 	BUILD_BUG_ON_NOT_POWER_OF_2(TASK_REPORT_MAX);
 
-	if (tsk_state == TASK_IDLE)
+	if ((tsk_state & TASK_IDLE) == TASK_IDLE)
 		state = TASK_REPORT_IDLE;
 
 	/*
@@ -1679,7 +1679,7 @@ static inline unsigned int __task_state_index(unsigned int tsk_state,
 	 * to userspace, we can make this appear as if the task has gone through
 	 * a regular rt_mutex_lock() call.
 	 */
-	if (tsk_state == TASK_RTLOCK_WAIT)
+	if (tsk_state & TASK_RTLOCK_WAIT)
 		state = TASK_UNINTERRUPTIBLE;
 
 	return fls(state);
-- 
2.41.0





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