We need to traverse every lru in the list_lrus in some routines, but skip
the non memcg aware lru. Actually, we can only add the memcg aware lrus to
the list. This can be efficient.
Signed-off-by: Muchun Song <songmuchun@xxxxxxxxxxxxx>
---
mm/list_lru.c | 25 +++++++++++--------------
1 file changed, 11 insertions(+), 14 deletions(-)
diff --git a/mm/list_lru.c b/mm/list_lru.c
index e86d4d055d3c..bed699edabe5 100644
--- a/mm/list_lru.c
+++ b/mm/list_lru.c
@@ -18,8 +18,16 @@
static LIST_HEAD(list_lrus);
static DEFINE_MUTEX(list_lrus_mutex);
+static inline bool list_lru_memcg_aware(struct list_lru *lru)
+{
+ return lru->memcg_aware;
+}
+
static void list_lru_register(struct list_lru *lru)
{
+ if (!list_lru_memcg_aware(lru))
+ return;
+
mutex_lock(&list_lrus_mutex);
list_add(&lru->list, &list_lrus);
mutex_unlock(&list_lrus_mutex);
@@ -27,6 +35,9 @@ static void list_lru_register(struct list_lru *lru)
static void list_lru_unregister(struct list_lru *lru)
{
+ if (!list_lru_memcg_aware(lru))
+ return;
+
mutex_lock(&list_lrus_mutex);
list_del(&lru->list);
mutex_unlock(&list_lrus_mutex);
@@ -37,11 +48,6 @@ static int lru_shrinker_id(struct list_lru *lru)
return lru->shrinker_id;
}
-static inline bool list_lru_memcg_aware(struct list_lru *lru)
-{
- return lru->memcg_aware;
-}
-
static inline struct list_lru_one *
list_lru_from_memcg_idx(struct list_lru_node *nlru, int idx)
{
@@ -460,9 +466,6 @@ static int memcg_update_list_lru(struct list_lru *lru,
{
int i;
- if (!list_lru_memcg_aware(lru))
- return 0;
-
for_each_node(i) {
if (memcg_update_list_lru_node(&lru->node[i],
old_size, new_size))
@@ -485,9 +488,6 @@ static void memcg_cancel_update_list_lru(struct list_lru *lru,
{
int i;
- if (!list_lru_memcg_aware(lru))
- return;
-
for_each_node(i)
memcg_cancel_update_list_lru_node(&lru->node[i],
old_size, new_size);
@@ -546,9 +546,6 @@ static void memcg_drain_list_lru(struct list_lru *lru,
{
int i;
- if (!list_lru_memcg_aware(lru))
- return;
-
for_each_node(i)
memcg_drain_list_lru_node(lru, i, src_idx, dst_memcg);
}
--
2.11.0
