Re: [PATCH] xdrstdio_create buffers do not output encoded values on ppc

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On Thu, 2018-06-28 at 12:40 -0400, Steve Dickson wrote:
> 
> On 06/28/2018 12:17 PM, Trond Myklebust wrote:
> > On Thu, 2018-06-28 at 11:29 -0400, Steve Dickson wrote:
> > > From: Daniel Sands <dnsands@xxxxxxxxxx>
> > > 
> > > The cause is that the xdr_putlong uses a long to store the
> > > converted value, then passes it to fwrite as a byte buffer.
> > > Only the first 4 bytes are written, which is okay for a LE
> > > system after byteswapping, but writes all zeroes on BE systems.
> > > 
> > > Fixes: https://bugzilla.redhat.com/show_bug.cgi?id=1261738
> > > 
> > > Signed-off-by: Steve Dickson <steved@xxxxxxxxxx>
> > > ---
> > >  src/xdr_stdio.c | 10 +++++-----
> > >  1 file changed, 5 insertions(+), 5 deletions(-)
> > > 
> > > diff --git a/src/xdr_stdio.c b/src/xdr_stdio.c
> > > index 4410262..b415f61 100644
> > > --- a/src/xdr_stdio.c
> > > +++ b/src/xdr_stdio.c
> > > @@ -103,10 +103,10 @@ xdrstdio_getlong(xdrs, lp)
> > >  	XDR *xdrs;
> > >  	long *lp;
> > >  {
> > > -
> > > -	if (fread(lp, sizeof(int32_t), 1, (FILE *)xdrs-
> > > >x_private)
> > > != 1)
> > > +	u_int32_t mycopy;
> > > +	if (fread(&mycopy, sizeof(u_int32_t), 1, (FILE *)xdrs-
> > > > x_private) != 1)
> > > 
> > >  		return (FALSE);
> > > -	*lp = (long)ntohl((u_int32_t)*lp);
> > > +	*lp = (long)ntohl(mycopy);
> > >  	return (TRUE);
> > >  }
> > >  
> > > @@ -115,9 +115,9 @@ xdrstdio_putlong(xdrs, lp)
> > >  	XDR *xdrs;
> > >  	const long *lp;
> > >  {
> > > -	long mycopy = (long)htonl((u_int32_t)*lp);
> > > +	u_int32_t mycopy = (u_int32_t)htonl((u_int32_t)*lp);
> > >  
> > > -	if (fwrite(&mycopy, sizeof(int32_t), 1, (FILE *)xdrs-
> > > > x_private) != 1)
> > > 
> > > +	if (fwrite(&mycopy, sizeof(u_int32_t), 1, (FILE *)xdrs-
> > > > x_private) != 1)
> > > 
> > >  		return (FALSE);
> > >  	return (TRUE);
> > >  }
> > 
> > Hmm... Given that most setups today tend to be 64-bit, shouldn't
> > there
> > also be bounds checking in the above 'xdrstdio_putlong()' in order
> > to
> > make it safe?
> > 
> > Something like
> > 
> > if ((long)(u_int32_t)*lp != *lp) return (FALSE);
> > 
> 
> Sorry... I'm not following this... why is this necessary
> and what are you making safe?
> 
A long integer on most 64-bit systems is 64-bit long, but in the code
above, you are pushing that value into a 32-bit big-endian integer. So
a safe implementation would normally check for whether or not the 64-
bit value is getting truncated when it gets cast to u_int32_t, and
would throw an error in the case where the long really does not fit
into that 32-bit integer.

-- 
Trond Myklebust
CTO, Hammerspace Inc
4300 El Camino Real, Suite 105
Los Altos, CA 94022
www.hammer.space

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