Paul E. McKenney <paulmck@xxxxxxxxxxxxxxxxxx> wrote:
> +#define rcu_access_pointer(p, c) \
Why is there a need for 'c'?
> +#define rcu_dereference_protect(p, c) \
I'd prefer rcu_dereference_protected(), I think. This macro doesn't protect
anything. Also, again, why the need for 'c'?
For instance, in:
static struct nfs_delegation *nfs_detach_delegation_locked(struct nfs_inode *nfsi, const nfs4_stateid *stateid)
{
struct nfs_delegation *delegation =
rcu_dereference_protected(nfsi->delegation, ????);
what would be the condition? That the spinlock is held? That's a condition
for calling the function.
And in:
void nfs_inode_return_delegation_noreclaim(struct inode *inode)
{
struct nfs_client *clp = NFS_SERVER(inode)->nfs_client;
struct nfs_inode *nfsi = NFS_I(inode);
struct nfs_delegation *delegation;
if (rcu_access_pointer(nfsi->delegation, ????) != NULL) {
what would be the condition here? There's no lock to check - that's the whole
point of the macro. I also can't give it nfsi->delegation to check as the
value may change between the two accesses.
David
--
To unsubscribe from this list: send the line "unsubscribe linux-nfs" in
the body of a message to majordomo@xxxxxxxxxxxxxxx
More majordomo info at http://vger.kernel.org/majordomo-info.html
