On 2/27/24 07:57, Stefan Hajnoczi wrote: > virtio_fs_sysfs_exit() is called by: > - static int __init virtio_fs_init(void) > - static void __exit virtio_fs_exit(void) > > Remove __exit from virtio_fs_sysfs_exit() since virtio_fs_init() is not > an __exit function. > > Reported-by: kernel test robot <lkp@xxxxxxxxx> > Closes: https://lore.kernel.org/oe-kbuild-all/202402270649.GYjNX0yw-lkp@xxxxxxxxx/ > Signed-off-by: Stefan Hajnoczi <stefanha@xxxxxxxxxx> Reviewed-by: Randy Dunlap <rdunlap@xxxxxxxxxxxxx> Tested-by: Randy Dunlap <rdunlap@xxxxxxxxxxxxx> # build-tested Thanks. > --- > fs/fuse/virtio_fs.c | 2 +- > 1 file changed, 1 insertion(+), 1 deletion(-) > > diff --git a/fs/fuse/virtio_fs.c b/fs/fuse/virtio_fs.c > index 62a44603740c..948b49c2460d 100644 > --- a/fs/fuse/virtio_fs.c > +++ b/fs/fuse/virtio_fs.c > @@ -1588,7 +1588,7 @@ static int __init virtio_fs_sysfs_init(void) > return 0; > } > > -static void __exit virtio_fs_sysfs_exit(void) > +static void virtio_fs_sysfs_exit(void) > { > kset_unregister(virtio_fs_kset); > virtio_fs_kset = NULL; -- #Randy
