Re: alloc_netdev() and 32 byte or 32 bit alignment???

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On 5/18/07, Sam Ravnborg <sam@xxxxxxxxxxxx> wrote:
On Fri, May 18, 2007 at 05:10:02PM +0530, pradeep singh wrote:
> Hi ,
>
> following code snippet is self evident in what it does -
>
> truct net_device *alloc_netdev(int sizeof_priv, const char *name,
>               void (*setup)(struct net_device *))
> {
>       void *p;
>       struct net_device *dev;
>       int alloc_size;
>
>       /* ensure 32-byte alignment of both the device and private area */
>       alloc_size = (sizeof(*dev) + NETDEV_ALIGN_CONST) & ~NETDEV_ALIGN_CONST;
>       alloc_size += sizeof_priv + NETDEV_ALIGN_CONST;
>
>       p = kzalloc(alloc_size, GFP_KERNEL);
>       if (!p) {
>               printk(KERN_ERR "alloc_dev: Unable to allocate device.\n");
>               return NULL;
>       }
> [snip]
>
> Is the comment correct?
> Why is it 'ensure 32 byte alignment', instead of 32 bit alignment?
>
> What am i missing here?

Google turned up following useful link:
http://www.nabble.com/-RFC--changing-value-of-NETDEV_ALIGN-to-cacheline-size-t1620499.html
Thank you Sam.
This is really the answer i should have searched :-(.

A lesson to learn indeed.

Thank you once again.
--psr

snip:
The reason it's 32 is that old drivers depended on the
struct being at least 32-byte aligned because they would
embed structures DMA'd to/from the card in their private
area and just assumed that would be aligned enough for
the card's restrictions.

        Sam



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