During the 53 seconds, client send 30,000 packets to server; accordingly , server send all these packets back to client. These packets size is 2048 Bytes. so the bandwidth is about (not including ip, tcp, ethernet header) 30,000 * 2048 * 8 * 2 / 53 = 176.89Mb/s Why???????????????????????????????????????
Fast ethernet may be set to full duplex.
So, a 100Mbit/s interface is 100Mbit/s one way and 100Mbit/s the other way. So, yes, is 200Mbit/s.
Best Regards Lu - : send the line "unsubscribe linux-net" in the body of a message to majordomo@vger.kernel.org More majordomo info at http://vger.kernel.org/majordomo-info.html
--- Catalin(ux aka Dino) BOIE catab at deuroconsult.ro http://kernel.umbrella.ro/ - : send the line "unsubscribe linux-net" in the body of a message to majordomo@vger.kernel.org More majordomo info at http://vger.kernel.org/majordomo-info.html
