Re: UDP checksum elimination

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   From: sai narasimhamurthy <sai_narasi@yahoo.com>
   Date: Tue, 1 Jul 2003 20:16:14 -0700 (PDT)

   Does that mean there is no processing at the reciever
   too?? (for 0 checksum transmitted for UDP)

... ugh, this is why I never respond to beginner questions
on this list.

No, I am saying that if we have to make a copy between
user and kernel, there is no gain from eliminating the
checksum because it can be computed in parallel with
the data copy.
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