1 start, 8 data, and 1 stop bit = 10 bits per transferred byte. A standard ping packet contains 64 bytes -- 640 bits in this case. Transferring 640 bits at 9600 bits per second would take ~0.067 seconds. IOW, even with no other factors involved, it would take 67ms to cram the entire ping packet through that pipe. I'm with Glynn here -- if you're concerned about speed, consider a couple cheapo network cards and a crossover cable. -- Brian On Friday 13 July 2001 05:44 pm, Michael Peddemors wrote: > Glynn, you stumped me.. > Explain the 64*10 reasoning? > > On 13 Jul 2001 15:32:06 +0100, Glynn Clements wrote: > > Clearly a 1ms ping (with the default packet size of 64 bytes) is > > impossible over a 9600bps connection. Assuming 1 start bit and 1 stop > > bit, the transmission time each way is 64 * 10 / 9600 = 0.067 = 67ms, - : send the line "unsubscribe linux-net" in the body of a message to majordomo@vger.kernel.org
