On 27/05/20 04:18PM, Yicong Yang wrote: > Hi Pratyush, > > On 2020/5/26 0:14, Pratyush Yadav wrote: > > Hi Yicong, > > > > On 21/05/20 07:23PM, Yicong Yang wrote: > >> The controller can be shared with the firmware, which may cause race > >> problems. As most read/write/erase/lock/unlock of spi-nor flash are > >> composed of a set of operations, while the firmware may use the controller > >> and start its own operation in the middle of the process started by the > >> kernel driver, which may lead to the kernel driver's function broken. > >> > >> Bit[20] in HISI_SFC_V3XX_CMD_CFG register plays a role of a lock, to > >> protect the controller from firmware access, which means the firmware > >> cannot reach the controller if the driver set the bit. Add prepare/ > >> unprepare methods for the controller, we'll hold the lock in prepare > >> method and release it in unprepare method, which will solve the race > >> issue. > > I'm trying to understand the need for this change. What's wrong with > > performing the lock/unlock procedure in hisi_sfc_v3xx_exec_op()? You can > > probably do something like: > > > > hisi_sfc_v3xx_lock(); > > ret = hisi_sfc_v3xx_generic_exec_op(host, op, chip_select); > > hisi_sfc_v3xx_unlock(); > > return ret; > > if doing like this, suppose we perform a sequential operations like below: > > lock()->exec_op(cmd1)->unlock()->lock()->exec_op(cmd2)->unlock()->lock()->exec_op(cmd3)->unlock() > ^==========^is unlocked ^==========^is unlocked > > As shown above, we cannot lock the device continuously during the whole operations. Correct. My argument is based on the assumption that lock() and unlock() are cheap/fast operations. If you spend very little time in lock() and unlock(), it doesn't make a big difference if you do all 3 operations in one go or one at a time. In other words, since register write should be pretty fast, locking and unlocking should be pretty fast. If we don't spend a lot of time in lock() and unlock(), we don't gain a lot of performance by reducing those calls. > But if we use upper layer method then it looks like > > prepare()->exec_op(cmd1)->exec_op(cmd2)->exec_op(cmd3)->unprepare() > ^locked here ^unlocked here > > we can hold the lock during the all 3 operations' execution. If you still think doing all operations in one go is a better idea, I like Boris's idea of batching operations and its worth considering. > > What's the benefit of making upper layers do this? Acquiring the lock is > > a simple register write, so it should be relatively fast. Unless there > > is a lot of contention on the lock between the firmware and kernel, I > > would expect the performance impact to be minimal. Maybe you can run > > some benchmarks and see if there is a real difference. > > > >> Signed-off-by: Yicong Yang <yangyicong@xxxxxxxxxxxxx> > >> --- > >> drivers/spi/spi-hisi-sfc-v3xx.c | 41 ++++++++++++++++++++++++++++++++++++++++- > >> 1 file changed, 40 insertions(+), 1 deletion(-) > >> > >> diff --git a/drivers/spi/spi-hisi-sfc-v3xx.c b/drivers/spi/spi-hisi-sfc-v3xx.c > >> index e3b5725..13c161c 100644 > >> --- a/drivers/spi/spi-hisi-sfc-v3xx.c > >> +++ b/drivers/spi/spi-hisi-sfc-v3xx.c > >> @@ -163,7 +192,15 @@ static int hisi_sfc_v3xx_generic_exec_op(struct hisi_sfc_v3xx_host *host, > >> u8 chip_select) > >> { > >> int ret, len = op->data.nbytes; > >> - u32 config = 0; > >> + u32 config; > >> + > >> + /* > >> + * The lock bit is in the command register. Clear the command > >> + * field with lock bit held if it has been set in > >> + * .prepare(). > >> + */ > >> + config = readl(host->regbase + HISI_SFC_V3XX_CMD_CFG); > >> + config &= HISI_SFC_V3XX_CMD_CFG_LOCK; > > This will unlock the controller _before_ the driver issues > > hisi_sfc_v3xx_read_databuf(). I'm not very familiar with the hardware, > > but to me it seems like it can lead to a race. What if the firmware > > issues a command that over-writes the databuf (I assume this is shared > > between the two) before the driver gets a chance to copy that data to > > the kernel buffer? > > It won't unlock the controller if it has been locked in prepare(). It will clear > the other bits in the register other than the lock bit. For single operations, as > prepare() method is not called, the bit is 0 and it won't change here. Right. I misread the code. Sorry. -- Regards, Pratyush Yadav ______________________________________________________ Linux MTD discussion mailing list http://lists.infradead.org/mailman/listinfo/linux-mtd/