One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example: struct foo { int stuff; void *entry[]; }; instance = devm_kzalloc(dev, sizeof(struct foo) + sizeof(void *) * count, GFP_KERNEL); Instead of leaving these open-coded and prone to type mistakes, we can now use the new struct_size() helper: instance = devm_kzalloc(dev, struct_size(instance, entry, count), GFP_KERNEL); Signed-off-by: Gustavo A. R. Silva <gustavo@xxxxxxxxxxxxxx> --- drivers/mtd/nand/raw/jz4780_nand.c | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/drivers/mtd/nand/raw/jz4780_nand.c b/drivers/mtd/nand/raw/jz4780_nand.c index db4fa60..ac62395 100644 --- a/drivers/mtd/nand/raw/jz4780_nand.c +++ b/drivers/mtd/nand/raw/jz4780_nand.c @@ -352,7 +352,7 @@ static int jz4780_nand_probe(struct platform_device *pdev) return -ENODEV; } - nfc = devm_kzalloc(dev, sizeof(*nfc) + (sizeof(nfc->cs[0]) * num_banks), GFP_KERNEL); + nfc = devm_kzalloc(dev, struct_size(nfc, cs, num_banks), GFP_KERNEL); if (!nfc) return -ENOMEM; -- 2.7.4 ______________________________________________________ Linux MTD discussion mailing list http://lists.infradead.org/mailman/listinfo/linux-mtd/