28.02.2017 01:32, Roger House пишет:
# $_lpt1 = "lpr -l"
# $_lpt2 = "lpr -l -P lpt2"
# $_lpt3 = ""
# idle time in seconds before spooling out. Default: (20)
# $_printer_timeout = (20)
##############################################################################
However, these lines are not at all clear to me. What changes are
needed so
that lpt1 output goes to a disk file?
Try:
$_lpt1 = "cat > /tmp/file_name"
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