On Tue, Sep 22, 2015 at 6:18 AM, Vitaly Wool <vitalywool@xxxxxxxxx> wrote:
> Hi Dan,
>
> On Mon, Sep 21, 2015 at 6:17 PM, Dan Streetman <ddstreet@xxxxxxxx> wrote:
>> Please make sure to cc Seth also, he's the owner of zbud.
>
> Sure :)
>
> <snip>
>>> @@ -514,8 +552,17 @@ int zbud_reclaim_page(struct zbud_pool *pool, unsigned int retries)
>>> return -EINVAL;
>>> }
>>> for (i = 0; i < retries; i++) {
>>> - zhdr = list_tail_entry(&pool->lru, struct zbud_header, lru);
>>> - list_del(&zhdr->lru);
>>> + page = list_tail_entry(&pool->lru, struct page, lru);
>>> + zhdr = page_address(page);
>>> + list_del(&page->lru);
>>> + /* Uncompressed zbud page? just run eviction and free it */
>>> + if (page->flags & PG_uncompressed) {
>>> + page->flags &= ~PG_uncompressed;
>>> + spin_unlock(&pool->lock);
>>> + pool->ops->evict(pool, encode_handle(zhdr, FULL));
>>> + __free_page(page);
>>> + return 0;
>>
>> again, don't be redundant. change the function to handle full-sized
>> pages, don't repeat the function in an if() block for a special case.
>
> Well, this case is a little tricky. How to process a zbud page in
> zbud_reclaim_page() is defined basing on the assumption there is a
> zhdr at the beginning of the page. What can be done here IMV is either
> of the following:
aha, this is why you used the page flag.
> * add a constant magic number to zhdr and check for it, if the check
> fails, it is a type FULL page
> * add a CRC field to zhdr, if CRC check over assumed zhdr fails, it
> is a type FULL page
neither of those; you can't guarantee the magic number won't naturally
occur in a page.
> * use a field from struct page to indicate its type
sure, you could use a pre-existing field from struct page, like the
page->private field.
>
> The last option still looks better to me.
>
> ~vitaly
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