On Fri 05-04-13 12:08:40, Glauber Costa wrote:
> On 04/03/2013 07:29 PM, Michal Hocko wrote:
> > On Wed 03-04-13 16:58:48, Glauber Costa wrote:
> >> On 04/03/2013 01:11 PM, Li Zefan wrote:
> >>> Use css_get/css_put instead of mem_cgroup_get/put.
> >>>
> >>> Note, if at the same time someone is moving @current to a different
> >>> cgroup and removing the old cgroup, css_tryget() may return false,
> >>> and sock->sk_cgrp won't be initialized.
> >>>
> >>> Signed-off-by: Li Zefan <lizefan@xxxxxxxxxx>
> >>> ---
> >>> mm/memcontrol.c | 8 ++++----
> >>> 1 file changed, 4 insertions(+), 4 deletions(-)
> >>>
> >>> diff --git a/mm/memcontrol.c b/mm/memcontrol.c
> >>> index 23d0f6e..43ca91d 100644
> >>> --- a/mm/memcontrol.c
> >>> +++ b/mm/memcontrol.c
> >>> @@ -536,15 +536,15 @@ void sock_update_memcg(struct sock *sk)
> >>> */
> >>> if (sk->sk_cgrp) {
> >>> BUG_ON(mem_cgroup_is_root(sk->sk_cgrp->memcg));
> >>> - mem_cgroup_get(sk->sk_cgrp->memcg);
> >>> + css_get(&sk->sk_cgrp->memcg->css);
> >
> > I am not sure I understand this one. So we have a goup here (which means
> > that somebody already took a reference on it, right?) and we are taking
> > another reference. If this is released by sock_release_memcg then who
> > releases the previous one? It is not directly related to the patch
> > because this has been done previously already. Could you clarify
> > Glauber, please?
>
> This should be documented in the commit that introduced this, and it was
> one of the first bugs I've handled with this code.
>
> Bottom line, we can create sockets normally, and those will have process
> context. But we also can create sockets by cloning existing sockets. To
> the best of my knowledge, this is done by things like accept().
>
> Because those sockets are a clone of their ancestors, they also belong
> to a workload that should be limited. Also note that because they have
> cgroup context, we will eventually try to put them. So we need to grab
> an extra reference.
>
> socket_update_cgroup is always called at socket creation, and the
> original structures are filled with zeroes. Therefore cloning is the
> *only* path that takes us here with sk->sk_cgroup filled.
OK, I guess I understand.
Thanks for the clarification, Galuber!
--
Michal Hocko
SUSE Labs
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