Hi Suren,
On 2024/12/12 15:16, Suren Baghdasaryan wrote:
On Wed, Dec 11, 2024 at 12:56 AM Zhenhua Huang
<quic_zhenhuah@xxxxxxxxxxx> wrote:
/proc/allocinfo is full of callsites which are not called at all.
Let's only output if the callsite actually been invoked.
No, I disagree. Allocation that was never invoked is not the same as
no allocation at all. How would we know the difference if we filter
But it doesn't affect further display when it is actually called? why we
need to know the diff here...
The point from me is: up to now, the callsite hasn't been invoked, so it
can be ignored in the output.. The original output is really huge..
out the empty ones?
If you don't want to see all the unused sites, you can filter them in
the userspace. I also suspect that for practical purposes you would
want to filter small ones (below some threshold) as well.
Yeah, that's the expected way from us as well :)
Signed-off-by: Zhenhua Huang <quic_zhenhuah@xxxxxxxxxxx>
---
lib/alloc_tag.c | 10 ++++++----
1 file changed, 6 insertions(+), 4 deletions(-)
diff --git a/lib/alloc_tag.c b/lib/alloc_tag.c
index 35f7560a309a..06fb7eb5c0bc 100644
--- a/lib/alloc_tag.c
+++ b/lib/alloc_tag.c
@@ -95,10 +95,12 @@ static void alloc_tag_to_text(struct seq_buf *out, struct codetag *ct)
struct alloc_tag_counters counter = alloc_tag_read(tag);
s64 bytes = counter.bytes;
- seq_buf_printf(out, "%12lli %8llu ", bytes, counter.calls);
- codetag_to_text(out, ct);
- seq_buf_putc(out, ' ');
- seq_buf_putc(out, '\n');
+ if (bytes || counter.calls) {
+ seq_buf_printf(out, "%12lli %8llu ", bytes, counter.calls);
+ codetag_to_text(out, ct);
+ seq_buf_putc(out, ' ');
+ seq_buf_putc(out, '\n');
+ }
}
static int allocinfo_show(struct seq_file *m, void *arg)
--
2.25.1
