2024년 6월 10일 (월) 오전 6:03, Andrew Morton <akpm@xxxxxxxxxxxxxxxxxxxx>님이 작성: > > On Sun, 9 Jun 2024 00:21:14 +0900 Leesoo Ahn <lsahn@xxxxxxxxxx> wrote: > > > Setting 'limit' variable to 0 might seem like it means "no limit". But > > in the memblock API, 0 actually means the 'MEMBLOCK_ALLOC_ACCESSIBLE' > > enum, which limits the physical address range based on > > 'memblock.current_limit'. This can be confusing. > > Does it? From my reading, this meaning applies to the range end > address, in memblock_find_in_range_node()? If your interpretation is > correct, this should be documented in the relevant memblock kerneldoc. IMO, regardless of memblock documentation, it better uses MEMBLOCK_ALLOC_ACCESSIBLE enum instead of 0 as a value for the variable. Best regards, Leesoo
