On Wed, 1 May 2024 18:30:40 +0300 Mike Rapoport <rppt@xxxxxxxxxx> wrote: > > > /* > > > * Parse early_reserve_mem=nn:align:name > > > */ > > > static int __init early_reserve_mem(char *p) > > > { > > > phys_addr_t start, size, align; > > > char *oldp; > > > int err; > > > > > > if (!p) > > > return -EINVAL; > > > > > > oldp = p; > > > size = memparse(p, &p); > > > if (p == oldp) > > > return -EINVAL; > > > > > > if (*p != ':') > > > return -EINVAL; > > > > > > align = memparse(p+1, &p); > > > if (*p != ':') > > > return -EINVAL; > > > > > > start = memblock_phys_alloc(size, align); > > > > So this will allocate the same physical location for every boot, if booting > > the same kernel and having the same physical memory layout? > > Up to kaslr that might use that location for the kernel image. > But it's the same as allocating from e820 after kaslr. > > And, TBH, I don't have good ideas how to ensure the same physical location > with randomization of the physical address of the kernel image. I'll try it out. Looking at arch/x86/boot/compressed/kaslr.c, if I read the code correctly, it creates up to a 100 slots to store the kernel. The method I used was to make sure that the allocation was always done at the top address of memory, which I think would in most cases never be assigned by KASLR. This looks to just grab the next available physical address, which KASLR can most definitely mess with. I would still like to get the highest address possible. -- Steve