On 2022/5/13 0:50, David Hildenbrand wrote: > On 12.05.22 15:26, Miaohe Lin wrote: >> On 2022/5/12 15:10, David Hildenbrand wrote: >>>>> If PG_isolated is still set, it will get cleared in the buddy when >>>>> freeing the page via >>>>> >>>>> page->flags &= ~PAGE_FLAGS_CHECK_AT_PREP; >>>> >>>> Yes, check_free_page only complains about flags belonging to PAGE_FLAGS_CHECK_AT_FREE and PG_isolated >>>> will be cleared in the buddy when freeing the page. But it might not be a good idea to reply on this ? >>>> IMHO, it should be better to clear the PG_isolated explicitly ourselves. >>> >>> I think we can pretty much rely on this handling in the buddy :) >> >> So is the below code change what you're suggesting? >> >> if (page_count(page) == 1) { >> /* page was freed from under us. So we are done. */ >> ClearPageActive(page); >> ClearPageUnevictable(page); >> - if (unlikely(__PageMovable(page))) >> - ClearPageIsolated(page); >> goto out; >> } > > Yeah, unless I am missing something important :) > >>> >>>> >>>>> >>>>>> >>>>>>> >>>>>>> >>>>>>> Also, I am not sure how reliable that page count check is here: if we'd >>>>>>> have another speculative reference to the page, we might see >>>>>>> "page_count(page) > 1" and not take that path, although the previous >>>>>>> owner released the last reference. >>>>>> >>>>>> IIUC, there should not be such speculative reference. The driver should have taken care >>>>>> of it. >>>>> >>>>> How can you prevent any kind of speculative references? >>>>> >>>>> See isolate_movable_page() as an example, which grabs a speculative >>>>> reference to then find out that the page is already isolated by someone >>>>> else, to then back off. >>>> >>>> You're right. isolate_movable_page will be an speculative references case. But the page count check here >>>> is just an optimization. If we encounter speculative references, it still works with useless effort of >>>> migrating to be released page. >>> >>> >>> Not really. The issue is that PAGE_FLAGS_CHECK_AT_FREE contains >>> PG_active and PG_unevictable. >>> >>> We only clear those 2 flags if "page_count(page) == 1". Consequently, >>> with a speculative reference, we'll run into the check_free_page_bad() >>> when dropping the last reference. >> >> It seems if a speculative reference happens after the "page_count(page) == 1" check, >> it's ok because we cleared the PG_active and PG_unevictable. And if it happens before >> the check, this code block is skipped and the page will be freed after migration. The >> PG_active and PG_unevictable will be correctly cleared when page is actually freed via >> __folio_clear_active. (Please see below comment) >> >>> >>> This is just shaky. Special casing on "page_count(page) == 1" for >>> detecting "was this freed by the owner" is not 100% water proof. >>> >>> In an ideal world, we'd just get rid of that whole block of code and let >>> the actual freeing code clear PG_active and PG_unevictable. But that >>> would require changes to free_pages_prepare(). >>> >>> >>> Now I do wonder, if we ever even have PG_active or PG_unevictable still >>> set when the page was freed by the owner in this code. IOW, maybe that >>> is dead code as well and we can just remove the whole shaky >>> "page_count(page) == 1" code block. >> >> Think about below common scene: Anonymous page is actively used by the sole owner process, so it >> will have PG_active set. Then process exited while vm tries to migrate that page. So the page >> should have refcnt == 1 while PG_active is set? Note normally PG_active should be cleared when >> the page is released: >> >> __put_single_page >> PageLRU >> __clear_page_lru_flags >> __folio_clear_active >> __folio_clear_unevictable >> >> But for isolated page, PageLRU is cleared. So when the isolated page is released, __clear_page_lru_flags >> won't be called. So we have to clear the PG_active and PG_unevictable here manully. So I think >> this code block works. Or am I miss something again? > > Let's assume the following: page as freed by the owner and we enter > unmap_and_move(). > > > #1: enter unmap_and_move() // page_count is 1 > #2: enter isolate_movable_page() // page_count is 1 > #2: get_page_unless_zero() // page_count is now 2 > #1: if (page_count(page) == 1) { // does not trigger > #2: put_page(page); // page_count is now 1 > #1: put_page(page); // page_count is now 0 -> freed > > > #1 will trigger __put_page() -> __put_single_page() -> > __page_cache_release() will not clear the flags because it's not an LRU > page at that point in time, right (-> isolated)? > > We did not run that code block that would clear PG_active and > PG_unevictable. > > Which still leaves the questions: > > a) If PG_active and PG_unevictable was cleared, where? > b) Why is that code block that conditionally clears the flags of any > value and why can't we simply drop it? > I took a more close look of the code today. And I think the current code works: There are 3 cases in unmap_and_move: 1.page is freed through "if (page_count(page) == 1)" code block. This works as PG_active and PG_unevictable are cleared here. 2. Failed to migrate the page. The page won't be release so we don't care about it. 3. The page is migrated successfully. The PG_active and PG_unevictable are cleared via folio_migrate_flags(): if (folio_test_clear_active(folio)) { VM_BUG_ON_FOLIO(folio_test_unevictable(folio), folio); folio_set_active(newfolio); } else if (folio_test_clear_unevictable(folio)) folio_set_unevictable(newfolio); For the above race case, the page won't be freed through "if (page_count(page) == 1)" code block. It will just be migrated and freed via put_page() after folio_migrate_flags() having cleared PG_active and PG_unevictable. Am I miss something again ? ;) Thanks a lot!