On 5/17/22 07:00, Jason Gunthorpe wrote:
It does change the generated code slightly. I don't know if this will
affect performance here or not. But just for completeness, here you go:
free_one_page() originally has this (just showing the changed parts):
mov 0x8(%rdx,%rax,8),%rbx
and $0x3f,%ecx
shr %cl,%rbx
and $0x7,
And after applying this diff:
diff --git a/mm/page_alloc.c b/mm/page_alloc.c
index 0e42038382c1..df1f8e9a294f 100644
+++ b/mm/page_alloc.c
@@ -482,7 +482,7 @@ unsigned long __get_pfnblock_flags_mask(const struct
page *page,
word_bitidx = bitidx / BITS_PER_LONG;
bitidx &= (BITS_PER_LONG-1);
- word = bitmap[word_bitidx];
+ word = READ_ONCE(bitmap[word_bitidx]);
return (word >> bitidx) & mask;
}
...it now does an extra memory dereference:
lea 0x8(%rdx,%rax,8),%rax
and $0x3f,%ecx
mov (%rax),%rbx
shr %cl,%rbx
and $0x7,%ebx
Where is the extra memory reference? 'lea' is not a memory reference,
it is just some maths?
If you compare this to the snippet above, you'll see that there is
an extra mov statement, and that one dereferences a pointer from
%rax:
mov (%rax),%rbx
Thanks for checking, John.
I don't want to have the READ_ONCE in __get_pfnblock_flags_mask
atm even though it's an extra memory dereference for specific
architecutre and specific compiler unless other callsites *do*
need it.
If a callpath is called under locking or not under locking then I
would expect to have two call chains clearly marked what their locking
conditions are. ie __get_pfn_block_flags_mask_unlocked() - and
__get_pfn_block_flags_mask_unlocked() would definitely clarify things,
and allow some clear documentation, good idea.
I haven't checked to see if some code could keep using the normal
__get_pfn_block_flags_mask(), but if it could, that would help with the
problem of keeping the fast path fast.
obviously clearly document and check what the locking requirements are
of the locked path.
IMHO putting a READ_ONCE on something that is not a memory load from
shared data is nonsense - if a simple == has a stability risk then so
does the '(word >> bitidx) & mask'.
Jason
Doing something like this:
int __x = y();
int x = READ_ONCE(__x);
is just awful! I agree. Really, y() should handle any barriers, because
otherwise it really does look pointless, and people reading the code
need something that is clearer. My first reaction was that this was
pointless and wrong, and it turns out that that's only about 80% true:
as long as LTO-of-the-future doesn't arrive, and as long as no one
refactors y() to be inline.
thanks,
--
John Hubbard
NVIDIA