On Fri 22-07-11 08:49:27, KAMEZAWA Hiroyuki wrote: > On Thu, 21 Jul 2011 14:42:23 +0200 > Michal Hocko <mhocko@xxxxxxx> wrote: > > > On Thu 21-07-11 13:47:04, Michal Hocko wrote: > > > On Thu 21-07-11 19:30:51, KAMEZAWA Hiroyuki wrote: > > > > On Thu, 21 Jul 2011 09:58:24 +0200 > > > > Michal Hocko <mhocko@xxxxxxx> wrote: > > [...] > > > > > --- a/mm/memcontrol.c > > > > > +++ b/mm/memcontrol.c > > > > > @@ -2166,7 +2165,8 @@ static void drain_all_stock(struct mem_cgroup *root_mem, bool sync) > > > > > > > > > > for_each_online_cpu(cpu) { > > > > > struct memcg_stock_pcp *stock = &per_cpu(memcg_stock, cpu); > > > > > - if (test_bit(FLUSHING_CACHED_CHARGE, &stock->flags)) > > > > > + if (root_mem == stock->cached && > > > > > + test_bit(FLUSHING_CACHED_CHARGE, &stock->flags)) > > > > > flush_work(&stock->work); > > > > > > > > Doesn't this new check handle hierarchy ? > > > > css_is_ancestor() will be required if you do this check. > > > > > > Yes you are right. Will fix it. I will add a helper for the check. > > > > Here is the patch with the helper. The above will then read > > if (mem_cgroup_same_or_subtree(root_mem, stock->cached)) > > > > --- > > From b963a9f4dac61044daac49700f84b7819d7c2f53 Mon Sep 17 00:00:00 2001 > > From: Michal Hocko <mhocko@xxxxxxx> > > Date: Thu, 21 Jul 2011 13:54:13 +0200 > > Subject: [PATCH] memcg: add mem_cgroup_same_or_subtree helper > > > > We are checking whether a given two groups are same or at least in the > > same subtree of a hierarchy at several places. Let's make a helper for > > it to make code easier to read. > > > > Signed-off-by: Michal Hocko <mhocko@xxxxxxx> > > Acked-by: KAMEZAWA Hiroyuki <kamezawa.hiroyu@xxxxxxxxxxxxxx> Thanks -- Michal Hocko SUSE Labs SUSE LINUX s.r.o. Lihovarska 1060/12 190 00 Praha 9 Czech Republic -- To unsubscribe, send a message with 'unsubscribe linux-mm' in the body to majordomo@xxxxxxxxx. For more info on Linux MM, see: http://www.linux-mm.org/ . Fight unfair telecom internet charges in Canada: sign http://stopthemeter.ca/ Don't email: <a href=mailto:"dont@xxxxxxxxx"> email@xxxxxxxxx </a>