On Sat, 2 May 2020 10:10:55 -0400 Yafang Shao <laoar.shao@xxxxxxxxx> wrote: > A recent commit 9852ae3fe529 ("mm, memcg: consider subtrees in > memory.events") changes the behavior of memcg events, which will > consider subtrees in memory.events. But oom_kill event is a special one > as it is used in both cgroup1 and cgroup2. In cgroup1, it is displayed > in memory.oom_control. The file memory.oom_control is in both root memcg > and non root memcg, that is different with memory.event as it only in > non-root memcg. That commit is okay for cgroup2, but it is not okay for > cgroup1 as it will cause inconsistent behavior between root memcg and > non-root memcg. > > Here's an example on why this behavior is inconsistent in cgroup1. > root memcg > / > memcg foo > / > memcg bar > > Suppose there's an oom_kill in memcg bar, then the oon_kill will be > > root memcg : memory.oom_control(oom_kill) 0 > / > memcg foo : memory.oom_control(oom_kill) 1 > / > memcg bar : memory.oom_control(oom_kill) 1 > > For the non-root memcg, its memory.oom_control(oom_kill) includes its > descendants' oom_kill, but for root memcg, it doesn't include its > descendants' oom_kill. That means, memory.oom_control(oom_kill) has > different meanings in different memcgs. That is inconsistent. Then the user > has to know whether the memcg is root or not. > > If we can't fully support it in cgroup1, for example by adding > memory.events.local into cgroup1 as well, then let's don't touch > its original behavior. > > Fixes: 9852ae3fe529 ("mm, memcg: consider subtrees in memory.events") Nearly a year ago. Should we backport this into earlier kernels? > --- a/include/linux/memcontrol.h > +++ b/include/linux/memcontrol.h > @@ -783,6 +783,8 @@ static inline void memcg_memory_event(struct mem_cgroup *memcg, > atomic_long_inc(&memcg->memory_events[event]); > cgroup_file_notify(&memcg->events_file); > > + if (!cgroup_subsys_on_dfl(memory_cgrp_subsys)) > + break; > if (cgrp_dfl_root.flags & CGRP_ROOT_MEMORY_LOCAL_EVENTS) > break; > } while ((memcg = parent_mem_cgroup(memcg)) &&