> On Wed 04-09-19 15:54:57, Park Sangwoo wrote:
> > On Tue 03-09-19 18:59:59, Park Sangwoo wrote:
> > > On Mon 02-09-19 13:34:54, Sangwoo� wrote:
> > >>> On Fri 30-08-19 18:25:53, Sangwoo wrote:
> > >>>> The highatomic migrate block can be increased to 1% of Total memory.
> > >>>> And, this is for only highorder ( > 0 order). So, this block size is
> > >>>> excepted during check watermark if allocation type isn't alloc_harder.
> > >>>>
> > >>>> It has problem. The usage of highatomic is already calculated at
> > >>> NR_FREE_PAGES.
> > >>>>> So, if we except total block size of highatomic, it's twice minus size of
> > >>> allocated
> > >>>>> highatomic.
> > >>>>> It's cause allocation fail although free pages enough.
> > >>>>>
> > >>>>> We checked this by random test on my target(8GB RAM).
> > >>>>>
> > >>>>> Binder:6218_2: page allocation failure: order:0, mode:0x14200ca
> > >>> (GFP_HIGHUSER_MOVABLE), nodemask=(null)
> > >>>>> Binder:6218_2 cpuset=background mems_allowed=0
> > >>>>
> > >>>> How come this order-0 sleepable allocation fails? The upstream kernel
> > >>>> doesn't fail those allocations unless the process context is killed by
> > >>>> the oom killer.
> > >>>
> > > >>> Most calltacks are zsmalloc, as shown below.
> > > >>
> > > >> What makes those allocations special so that they fail unlike any other
> > > >> normal order-0 requests? Also do you see the same problem with the
> > > >> current upstream kernel? Is it possible this is an Android specific
> > > >> issue?
> > > >
> > > > There is the other case of fail order-0 fail.
> > > > ----
> > > > hvdcp_opti: page allocation failure: order:0, mode:0x1004000(GFP_NOWAIT|__GFP_COMP), nodemask=(null)
> > >
> > > This is an atomic allocation and failing that one is not a problem
> > > usually. High atomic reservations might prevent GFP_NOWAIT allocation
> > > from suceeding but I do not see that as a problem. This is the primary
> > > purpose of the reservation.
> >
> > Thanks, your answer helped me. However, my suggestion is not to modify the use and management of the high atomic region,
> > but to calculate the exact free size of the highatomic so that fail does not occur for previously shared cases.
> >
> > In __zone_water_mark_ok(...) func, if it is not atomic allocation, high atomic size is excluded.
> >
> > bool __zone_watermark_ok(struct zone *z,
> > ...
> > {
> > ...
> > if (likely(!alloc_harder)) {
> > free_pages -= z->nr_reserved_highatomic;
> > ...
> > }
> >
> > However, free_page excludes the size already allocated by hiahtomic.
> > If highatomic block is small(Under 4GB RAM), it could be no problem.
> > But, the larger the memory size, the greater the chance of problems.
> > (Becasue highatomic size can be increased up to 1% of memory)
>
> I still do not understand. NR_FREE_PAGES should include the amount of
> hhighatomic reserves, right. So reducing the free_pages for normal
> allocations just makes sense. Or what do I miss?
You are right. But z->nr_reserved_highatomic value is total size of
highatomic migrate type per zone.
nr_reserved_highatomic = (# of allocated of highatomic) + (# of free list of highatomic).
And (# of allocated of hiagatomic) is already excluded at NR_FREE_PAGES.
So, if reducing nr_reserved_highatomic at NR_FREE_PAGES,
the (# of allocated of highatomic) is double reduced.
So I proposal that only (# of free list of highatomic) is reduced at NR_FREE_PAGE.
if (likely(!alloc_harder)) {
- free_pages -= z->nr_reserved_highatomic;
+ free_pages -= zone_page_state(z, NR_FREE_HIGHATOMIC_PAGES);
} else {
>
> I am sorry but I find your reasoning really hard to follow.
