> On Thu, 2011-04-21 at 10:29 +0900, KOSAKI Motohiro wrote:
> > And one correction.
> > ------------------------------------------------------------------
> > static ssize_t comm_write(struct file *file, const char __user *buf,
> > size_t count, loff_t *offset)
> > {
> > struct inode *inode = file->f_path.dentry->d_inode;
> > struct task_struct *p;
> > char buffer[TASK_COMM_LEN];
> >
> > memset(buffer, 0, sizeof(buffer));
> > if (count > sizeof(buffer) - 1)
> > count = sizeof(buffer) - 1;
> > if (copy_from_user(buffer, buf, count))
> > return -EFAULT;
> >
> > p = get_proc_task(inode);
> > if (!p)
> > return -ESRCH;
> >
> > if (same_thread_group(current, p))
> > set_task_comm(p, buffer);
> > else
> > count = -EINVAL;
> > ------------------------------------------------------------------
> >
> > This code doesn't have proper credential check. IOW, you forgot to
> > pthread_setuid_np() case.
>
> Sorry, could you expand on this a bit? Google isn't coming up with much
> for pthread_setuid_np. Can a thread actually end up with different uid
> then the process it is a member of?
Yes. Linux kernel _always_ only care per-thread uid.
glibc 2.3.3 or earlier, it use kernel syscall straight forward. and then
userland application also don't have a way to change per-process uid.
glbc 2.3.4 or later, glibc implement per-process setuid by using signal
for inter thread communication. (ie, every thread call setuid() syscall
internally). Hm, currently pthread_setuid_np don't have proper exported
header file. so, parpaps, we need to only worry about syscall(NR_uid) and
old libc?
Anyway, If you see task_struct definition, you can easily find it has
cred.
Thanks.
>
> Or is same_thread_group not really what I think it is? What would be a
> better way to check that the two threads are members of the same
> process?
>
> thanks
> -john
>
>
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