Hi Rik, On Thu, Apr 28, 2011 at 8:46 AM, Rik van Riel <riel@xxxxxxxxxx> wrote: > On 04/26/2011 12:25 PM, Minchan Kim wrote: > >> But this approach has a problem on contiguous pages. >> In this case, my idea can not work since friend pages are isolated, too. >> It means prev_page->next == next_page always is false and both pages are >> not >> LRU any more at that time. It's pointed out by Rik at LSF/MM summit. >> So for solving the problem, I can change the idea. >> I think we don't need both friend(prev, next) pages relation but >> just consider either prev or next page that it is still same LRU. > >> Any comment? > > If the friend pages are isolated too, then your condition > "either prev or next page that it is still same LRU" is > likely to be false, no? H - P1 - P2 - P3 - P4 - P5 - P6 - P7 - P8 - P9 - P10 - T assume : we isolate pages P3~P7 and we consider only next pointer. H - P1 - P2 - P8 - P9 - P10 - T If we start to putback P7 as starting point, next P8 is valid so, H - P1 - P2 - P7 - P8 - P9 - P10 - T Then, if we consider P6, next P7 is valid, too. So, H - P1 - P2 - P6 - P7 - P8 - P9 - P10 - T continue until P3. -- Kind regards, Minchan Kim -- To unsubscribe, send a message with 'unsubscribe linux-mm' in the body to majordomo@xxxxxxxxxx For more info on Linux MM, see: http://www.linux-mm.org/ . Fight unfair telecom internet charges in Canada: sign http://stopthemeter.ca/ Don't email: <a href=mailto:"dont@xxxxxxxxx";> email@xxxxxxxxx </a>