Hi Mike, On Wed, Jan 16, 2019 at 03:44:12PM +0200, Mike Rapoport wrote: > The last parameter of memblock_alloc_from() is the lower limit for the > memory allocation. When it is 0, the call is equivalent to > memblock_alloc(). > > Signed-off-by: Mike Rapoport <rppt@xxxxxxxxxxxxx> Acked-by: Paul Burton <paul.burton@xxxxxxxx> # MIPS part Thanks, Paul