Re: [PATCH RESEND] slab: introduce the flag SLAB_MINIMIZE_WASTE

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On Thu, 26 Apr 2018, Mikulas Patocka wrote:

> > Hmmm... order 4 for these caches may cause some concern. These should stay
> > under costly order I think. Otherwise allocations are no longer
> > guaranteed.
>
> You said that slub has fallback to smaller order allocations.

Yes it does...

> The whole purpose of this "minimize waste" approach is to use higher-order
> allocations to use memory more efficiently, so it is just doing its job.
> (for these 3 caches, order-4 really wastes less memory than order-3 - on
> my system TCPv6 and sighand_cache have size 2112, task_struct 2752).

Hmmm... Ok if the others are fine with this as well. I got some pushback
there in the past.

> We could improve the fallback code, so that if order-4 allocation fails,
> it tries order-3 allocation, and then falls back to order-0. But I think
> that these failures are rare enough that it is not a problem.

I also think that would be too many fallbacks.

> > > +		/* Increase order even more, but only if it reduces waste */
> > > +		if (test_order_obj <= 32 &&
> >
> > Where does the 32 come from?
>
> It is to avoid extremely high order for extremely small slabs.
>
> For example, see kmalloc-96.
> 10922 96-byte objects would fit into 1MiB
> 21845 96-byte objects would fit into 2MiB

That is the result of considering absolute byte wastage..

> The algorithm would recognize this one more object that fits into 2MiB
> slab as "waste reduction" and increase the order to 2MiB - and we don't
> want this.
>
> So, the general reasoning is - if we have 32 objects in a slab, then it is
> already considered that wasted space is reasonably low and we don't want
> to increase the order more.
>
> Currently, kmalloc-96 uses order-0 - that is reasonable (we already have
> 42 objects in 4k page, so we don't need to use higher order, even if it
> wastes one-less object).


The old code uses the concept of a "fraction" to calculate overhead. The
code here uses absolute counts of bytes. Fraction looks better to me.




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