I am trying to understand the comment in zone_watermark_fast() that for
the case
of an order-0 allocation, it is ok to return true without considering
zone->nr_reserved_highatomic.
Suppose that:
1)CONFIG_CMA = n
2)zone_page_state(z, NR_FREE_PAGES) > zone->watermark[WMARK_MIN]
3)There is only one page which is MIGRATE_MOVABLE; all others are
MIGRATE_HIGHATOMIC.
4)There is one zone, so zone->lowmem_reserve = 0
For an order 0 GFP_KERNEL allocation:
zone_watermark_fast() returns true due to not considering the amount of
highatomic memory. rmqueue() finds the page in the MIGRATE_MOVEABLE
freelist
and returns it.
But I was expecting that the last available pages in the system would be
reserved for allocations with ALLOC_HARDER/ALLOC_HIGH set. For example,
order-0 atomic allocations.
What am I getting wrong here?
Regarding assumption 2&3)-
For an device with 2Gb memory:
the table above init_per_zone_wmark_min() shows that min_free_kbytes =
5792k.
This would be ~1448 pages.
reserve_highatomic_pageblock() caps highatomic pages at 1% of zone. This
would be 2^31/(2^12 * 100) ~= 5242 pages.
--Patrick
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