On Thu, Dec 21, 2017 at 02:48:10PM -0700, Ross Zwisler wrote:
> On Tue, Dec 19, 2017 at 08:58:23AM -0800, Matthew Wilcox wrote:
> > From: Matthew Wilcox <mawilcox@xxxxxxxxxxxxx>
> >
> > The __cond_lock macro expects the function to return 'true' if the lock
> > was acquired and 'false' if it wasn't. We have another common calling
> > convention in the kernel, which is returning 0 on success and an errno
> > on failure. It's hard to use the existing __cond_lock macro for those
> > kinds of functions, so introduce __cond_lock_err() and convert the
> > two existing users.
>
> This is much cleaner! One quick issue below.
>
> > Signed-off-by: Matthew Wilcox <mawilcox@xxxxxxxxxxxxx>
> > ---
> > include/linux/compiler_types.h | 2 ++
> > include/linux/mm.h | 9 ++-------
> > mm/memory.c | 9 ++-------
> > 3 files changed, 6 insertions(+), 14 deletions(-)
> >
> > diff --git a/include/linux/compiler_types.h b/include/linux/compiler_types.h
> > index 6b79a9bba9a7..ff3c41c78efa 100644
> > --- a/include/linux/compiler_types.h
> > +++ b/include/linux/compiler_types.h
> > @@ -16,6 +16,7 @@
> > # define __acquire(x) __context__(x,1)
> > # define __release(x) __context__(x,-1)
> > # define __cond_lock(x,c) ((c) ? ({ __acquire(x); 1; }) : 0)
> > +# define __cond_lock_err(x,c) ((c) ? 1 : ({ __acquire(x); 0; }))
> ^
> I think we actually want this to return c here ^
Then you want to use ((c) ?: ...), to avoid evaluating c twice.
- Josh Triplett
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