On Tue, 2010-12-14 at 13:42 -0500, Valdis.Kletnieks@xxxxxx wrote: > On Tue, 14 Dec 2010 14:51:33 +0800, Wu Fengguang said: > > > > > + /* (N * 10ms) on 2^N concurrent tasks */ > > > > + t = (hi - lo) * (10 * HZ) / 1024; > > > > > > Either I need more caffeine, or the comment doesn't match the code > > > if HZ != 1000? > > > > The "ms" in the comment may be confusing, but the pause time (t) is > > measured in jiffies :) Hope the below patch helps. > > No, I meant that 10 * HZ evaluates to different numbers depending what > the CONFIG_HZ parameter is set to - 100, 250, 1000, or some other > custom value. Does this code behave correctly on a CONFIG_HZ=100 kernel? 10*HZ = 10 seconds (10*HZ) / 1024 ~= 10 milliseconds -- To unsubscribe, send a message with 'unsubscribe linux-mm' in the body to majordomo@xxxxxxxxxx For more info on Linux MM, see: http://www.linux-mm.org/ . Fight unfair telecom policy in Canada: sign http://dissolvethecrtc.ca/ Don't email: <a href