From: Josh Poimboeuf
> Sent: 22 July 2016 18:46
..
> > >> +/*
> > >> + * Checks if a given pointer and length is contained by the current
> > >> + * stack frame (if possible).
> > >> + *
> > >> + * 0: not at all on the stack
> > >> + * 1: fully within a valid stack frame
> > >> + * 2: fully on the stack (when can't do frame-checking)
> > >> + * -1: error condition (invalid stack position or bad stack frame)
> > >> + */
> > >> +static noinline int check_stack_object(const void *obj, unsigned long len)
> > >> +{
> > >> + const void * const stack = task_stack_page(current);
> > >> + const void * const stackend = stack + THREAD_SIZE;
> > >
> > > That allows access to the entire stack, including the struct thread_info,
> > > is that what we want - it seems dangerous? Or did I miss a check
> > > somewhere else?
> >
> > That seems like a nice improvement to make, yeah.
> >
> > > We have end_of_stack() which computes the end of the stack taking
> > > thread_info into account (end being the opposite of your end above).
> >
> > Amusingly, the object_is_on_stack() check in sched.h doesn't take
> > thread_info into account either. :P Regardless, I think using
> > end_of_stack() may not be best. To tighten the check, I think we could
> > add this after checking that the object is on the stack:
> >
> > #ifdef CONFIG_STACK_GROWSUP
> > stackend -= sizeof(struct thread_info);
> > #else
> > stack += sizeof(struct thread_info);
> > #endif
> >
> > e.g. then if the pointer was in the thread_info, the second test would
> > fail, triggering the protection.
>
> FWIW, this won't work right on x86 after Andy's
> CONFIG_THREAD_INFO_IN_TASK patches get merged.
What ends up in the 'thread_info' area?
If it contains the fp save area then programs like gdb may end up requesting
copy_in/out directly from that area.
Interestingly the avx registers don't need saving on a normal system call
entry (they are all caller-saved) so the kernel stack can safely overwrite
that area.
Syscall entry probably ought to execute the 'zero all avx registers' instruction.
They do need saving on interrupt entry - but the stack used will be less.
David
��.n������g��� �a��� �&ޖ)���)��h���&������梷���� �Ǟ�m������)������^�����������v���O��zf������