Hello Ganesh,
On (07/04/16 17:21), Ganesh Mahendran wrote:
> > On (07/04/16 14:49), Ganesh Mahendran wrote:
> > [..]
> >> -static void zs_unregister_cpu_notifier(void)
> >> +static void __exit zs_unregister_cpu_notifier(void)
> >> {
> >
> > this __exit symbol is called from `__init zs_init()' and thus is
> > free to crash.
>
> I change code to force the code goto notifier_fail where the
> zs_unregister_cpu_notifier will be called.
> I tested with zsmalloc module buildin and built as a module.
sorry, not sure I understand what do you mean by this.
> Please correct me, if I miss something.
you have an __exit section function being called from
__init section:
static void __exit zs_unregister_cpu_notifier(void)
{
}
static int __init zs_init(void)
{
zs_unregister_cpu_notifier();
}
it's no good.
-ss
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